I'm trying to pass arguments to my program so that I can store them into an array. For some reason my IDE/compiler is treating the blank space in between arguments as an argument. I'm using bloodshed, but it doesn't say anything about a seperation character. Can anyone tell me what I'm doing wrong?
I'm doing something like this:
Bob Bill
that should be two parameters, but for some reason it returns three.
Bob Bill
that should be two parameters, but for some reason it returns three.
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![Pass Pass](/uploads/1/2/6/2/126248839/407954724.jpg)
Dante Shamest
It appears to work for me. The version of my Dev-C++ IDE is 4.9.9.2. One should note that the first parameter is always the name of your program.
This is the program I used for testing.
This picture shows how I passed the parameters.
[IMG]http://img438.imageshack.us/img438/724/parameters1fz.th.jpg[/IMG]
And this is my output.
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C++ does not allow to pass an entire array as an argument to a function. However, You can pass a pointer to an array by specifying the array's name without an index.
Pass 2 Executes Into Dev Calculator
If you want to pass a single-dimension array as an argument in a function, you would have to declare function formal parameter in one of following three ways and all three declaration methods produce similar results because each tells the compiler that an integer pointer is going to be received.
Pass 2 Executes Into Dev C Pdf
Way-1
Formal parameters as a pointer as follows −
Way-2
Formal parameters as a sized array as follows − Precision auto tune belair.
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Pass 2 Executes Into Dev C 5
Way-3
Formal parameters as an unsized array as follows −
Now, consider the following function, which will take an array as an argument along with another argument and based on the passed arguments, it will return average of the numbers passed through the array as follows −
Now, let us call the above function as follows −
When the above code is compiled together and executed, it produces the following result −
As you can see, the length of the array doesn't matter as far as the function is concerned because C++ performs no bounds checking for the formal parameters.